MESONS IN MY NEW THEORY OF NUCLEAR FORCES.
NAME OF SCIENTIST: MUNISHKUMAR.B.CHINNAKAR.
PLACE OF RESEARCH: MUNISHKUMAR'S SCIENCE RESEARCH CENTRE,NEAR BHAIRI WELL BOYER STREET(BHOVI STREET),SHORAPUR,KARNATAKA STATE,INDIA.
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E-mail:www.MChinnakar@gmail.com.
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E-mail:www.mchinnakar@gmail.com.
NUMBER OF CO-WORKERS : No co-workers.
DATE OF RESEARCH: JUL,11,2011.
DATE OF ENTRY OF RESEARCH WORK: JUL,11,2011.
DATE OF REENTRY OF RESEARCH WORK: JUL,12,2011.
Recall that in one of My Document I described that Polarisation of free space arround Proton is stronger and hence this Polarisation is tending to contract.This Polarisation is Characterised by Transformation Constant C=10^-3 and hence EM sensitive.But in case of Neutron Polarisation is stronger with saturation of EM nature and hence easily gravitates.This Polarisation arround Neutron is characterised by Transformation constant C=10^3 with secondary polarisation C=10.Bcause of saturation Neutron’s Polarisation is contracting and sensitive therefore easily decays after 1000secs in free space and 960secs in gravity space.
When reactional range of Polarisation is maximum[1],this size of Polarisation contracts and Quantises to yield Meson.This is as follows.
When neutron is at rest and Proton approaches,Polarisation(negative) of Proton Polarises the Polarisation of Neutron to Positive state.Here these two polarisation mixes such that a negative phi meson is created.Here Interaction in terms of Transformation Constant is 10^3.10^1.10^-3=10^1=C=1,in the direction towards Neutron.This type of Negative Phi meson is gravity sensitive(test it!).
When Proton is at rest and Neutron approaches,Proton’s Polarisation polarises the polarisation of Neutron to negative state.Here these two polarisation mixes such that a positive phi meson is created.Here Interaction in terms of Transformation Constant is 10^3.(1/10^1).10^-3=1/10^1=1/C=1,in the direction towards Proton.This type of Positive Phi meson is gravity sensitive(test it!).
When a Neutron and Neutron interacts Saturated EM Polarisations of either Neutrons polarise each other and redistributes with quantisation yielding a Particle neutral meson.Here interaction in terms of Transformation constant is (10^3.10^1).1/(10^3.10^1)=1 (as one particle’s Polariasation approaches another phenomenon is a Contraction process because of interaction,thus reciproacl of transformation constant is used),neutral phi meson created.This neutral Phi meson is not sensitive(test it!)
Spin state of Mesons is described by S=1/C^3.Spin triplet and singlet states can be explained when mesons brought to rest,V=C=1 and hence S=1 and for V=C=0,S=1/0=infinity=1.
Note that in My Theory ,Nucleons are not rotating arround one another.Here extra magnetic moment(as previously called as angular moment due to revolution of one nucleon arround another) arises due to extra shape of ellipsoid of Nucleon which is due to interaction.
REFERENCE: [1] NEW THEORY OF NUCLEAR FORCES,BY MUNISHKMAR.B.CHINNAKAR IN MUNISHKUMAR’S SCIENCE RESEARCH CENTRE,SHORAPUR,INDIA,PUBLISHED DATED 7/6/2010 AND 8/6/2010 IN MUNISHKUMAR CHINNAKAR’S BLOGGER IN GOOGLE.
Monday, July 11, 2011
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